given a scalene triangle with max size perimeter of 300m, create an exact mathematical model or computer model in c++.

all sides different lengths, hence the scalene part, can't be larger than 300m perimeter.

-- Anonymous, May 14, 2002

Answers

How does this keep happening?

-- Anonymous, May 14, 2002

I think Fred's science is so strong it's sending out rays.

-- Anonymous, May 14, 2002

Don't forget to carry the one. BEEYATCH!

-- Anonymous, May 14, 2002

all sides different lengths, hence the scalene part, can't be larger than 300m perimeter.

Well it's not hardly worth it then, is it?

-- Anonymous, May 14, 2002

Isn't a C++ what Ralphie got on his theme in A Christmas Story?

-- Anonymous, May 14, 2002

Can't breathe...too many math jokes...Ralphie's theme....hahahahaha...

-- Anonymous, May 14, 2002

I really don't understand. I Googled "MATH questions", and went through three pages of hits and didn't find this forum. Maybe there are nutters who are going through 37 pages of hits or something.

-- Anonymous, May 14, 2002

Maybe they are already on greenspun perusing school-related forums and come upon this one. Whatever way they're getting here, I love the "serve me now" attitude they always have. No please, no thank you, do they even come back to read the replies? They're nutters, all right. Flailers.

-- Anonymous, May 14, 2002

My computer doesn't have enough dilithium crystals to pull off this kind of an equation.

-- Anonymous, May 14, 2002

Maybe it needs a a new flux capacitor.

-- Anonymous, May 14, 2002

can't be larger than 300m perimeter.

Well it's not hardly worth it then, is it?

See, on Trading Spaces they just did some wonderful thinks with a 290m scalene triangle. Frank painted some bunnies and flowers on the outside, and then Dez turned it into a lamp.

-- Anonymous, May 14, 2002

Not until you provide your attempt first Emma Murphy!

-- Anonymous, May 14, 2002

This question would make more sense to me if there were a train involved coming from the opposite direction at 50 mph.

-- Anonymous, May 14, 2002

See, the question would make sense if there were an actual question. A mathematical or C++ model of a scalene triangle? Somehow I don't think that's what she's asking. You know, cause I can take a pencil and draw a scalene triangle (I'm just brilliant like that).

Shaking my head. We never had to do crap like that in calculus or computer science. Maybe I didn't get far enough.

-- Anonymous, May 14, 2002

There is a chance that one model is inadequate. Perhaps there are limitless models which meet the assigned parameters.

As for C++, that's just a discreet way to tell someone that you've had a b00b j0b.. Ladies??

-- Anonymous, May 14, 2002

God, this is so amusing. Has anyone ever trolled back to see if they got an answer to their question?

-- Anonymous, May 15, 2002

The task of making a scalene triangle with a perimeter of less than 300m is absurdly easy. Further, an "exact mathematical model" is just a measurement of the 3 side lengths, or 2 sides and the enclosed angle. From that, everything else can be calculated.

I've been thinking about the last puzzler from cartalk on NPR...

Basically, given two concentric circles and the length of a chord of the larger circle that is tangent to the inner circle, what is the area between the outer circle and the inner circle?

I drew a pretty little not-to-scale graphic... it's here.

You can also listen to the puzzler.

-- Anonymous, May 15, 2002

Screwed up the link to the audio of the puzzler... That was an earlier one. The real audio link is here.

-- Anonymous, May 15, 2002

I love the Car Talk guys, but as soon as I read:

"They want to make sure they measurement the floor area exactly, because they don't want to buy any extra paint."

...I lost interest. Who says that all mechanics aren't meatheads?

-- Anonymous, May 15, 2002

Fred, is that a diagram in your pocket or are you just happy to see me?

-- Anonymous, May 16, 2002

If we are given the 2 circles, that means we know the radii. Let's call them r1 and r2. Then, the length of the chord is irrelevant. Area of the difference can be described as A = Pi(r1^2-r2^2)

Let's say the meathead mechanics (my friends) cannot determine the radius of either circle.. BUT they have a way to measure angles. They could make a right triangle from the center, going to the point where the chord meets the outer circle. Call the cantral angle a. Then, r1 = L/2sin a and r2 = L/2tan a. But if they had equipment to measure the chord and the angle, why the F would they bother do use MATH to such extent when the puzzle was just a lesson in paying attention??

-- Anonymous, May 16, 2002

I forgot to say that "L" is the length of chord

-- Anonymous, May 16, 2002

I think that went without saying.

-- Anonymous, May 16, 2002

Let's say the meathead mechanics (my friends) cannot determine the radius of either circle.. BUT they have a way to measure angles.

We could say that, but it would be changing the problem. The only measurement we have is it the length of the chord.

Now, we can create a right triangle of sides r1, L/2, and r2 (hypotenuse).

... and on that note, I just found why I couldn't solve it before. Stupid negative sign. I've got this one figured out, yo. My science is once again tight.

-- Anonymous, May 16, 2002

Well, fred, making the assumption that they can measure angles is changing the problem too...

-- Anonymous, May 16, 2002

Never mind that last comment

-- Anonymous, May 16, 2002